SOLUTION: Find a quadratic model for this sequence. -4, -4, -3, -1, 2 A.) {{{y = 0.5x^2}}} - {{{0.5x - 4}}} B.) {{{y = 0.5x^2}}} - {{{1.5x - 3}}} C.) {{{y = 4.5x^2}}} - {{{21.5x+21}}}

Algebra ->  Test -> SOLUTION: Find a quadratic model for this sequence. -4, -4, -3, -1, 2 A.) {{{y = 0.5x^2}}} - {{{0.5x - 4}}} B.) {{{y = 0.5x^2}}} - {{{1.5x - 3}}} C.) {{{y = 4.5x^2}}} - {{{21.5x+21}}}      Log On


   

Question 1081258: Find a quadratic model for this sequence.
-4, -4, -3, -1, 2
A.) y+=+0.5x%5E2 - 0.5x+-+4
B.) y+=+0.5x%5E2 - 1.5x+-+3
C.) y+=+4.5x%5E2 - 21.5x%2B21
D.) y+=+-4.5x%5E2 + 21.4x+-+21
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
-4 | | -4 | | -3 | |+-1 | |+2
Differences are:
-4 | | -4 | | -3 | |+-1 | |+2
-----0-----1---------2-------+3
----------1-------+1-------+1


a%5Bn+%5D=%28+1%2F2%29+%28n%5E2+-+3+n+-+6%29 (for all terms given)
a%5Bn%5D=0.5n%5E2+-0.5%2A3n+-+0.5%2A6
a%5Bn%5D=0.5n%5E2+-1.5n+-+3

answer: B.) y+=+0.5x%5E2-1.5x+-+3