SOLUTION: Find Pk + 1 if Pk = 7 + 13 + 19 +...+[6(k - 1)+1] + (6k + 1) A.) 7 + 13 + 19 + …+[6(k - 1) + 1] + (6k + 1) + [6(k + 1) + 1] B.) 8 + 14 + 20 + …+[7(k - 1) + 1] + (7k + 1) C.)
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-> SOLUTION: Find Pk + 1 if Pk = 7 + 13 + 19 +...+[6(k - 1)+1] + (6k + 1) A.) 7 + 13 + 19 + …+[6(k - 1) + 1] + (6k + 1) + [6(k + 1) + 1] B.) 8 + 14 + 20 + …+[7(k - 1) + 1] + (7k + 1) C.)
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Question 1081248
:
Find Pk + 1 if
Pk = 7 + 13 + 19 +...+[6(k - 1)+1] + (6k + 1)
A.) 7 + 13 + 19 + …+[6(k - 1) + 1] + (6k + 1) + [6(k + 1) + 1]
B.) 8 + 14 + 20 + …+[7(k - 1) + 1] + (7k + 1)
C.) 7 + 13 + 19 + …+(6k + 1)
C.) 7 + 13 + 19 + ...+[6(k - 1) + 1] + (6k +1) + (6k + 2)
Answer by
ikleyn(52803)
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https://www.algebra.com/algebra/homework/playground/test.faq.question.1081311.html
By the way, your notation A), B), C), C) is WRONG.
The correct notation is A), B), C), D).
