Question 1080922: A northbound train left at midnight. Three hours later, a southbound train left the same station.
At 6 a.m. the two trains were 330 miles apart. Find the rate of each train if the northbound train traveled 10 miles per hour faster than the southbound train.
Draw graph to display problem.
Found 3 solutions by Fombitz, josmiceli, MathTherapy:
Answer by Fombitz(32388)   (Show Source):
Answer by josmiceli(19441)  (Show Source):
Answer by MathTherapy(10555)  (Show Source):
You can put this solution on YOUR website! A northbound train left at midnight. Three hours later, a southbound train left the same station.
At 6 a.m. the two trains were 330 miles apart. Find the rate of each train if the northbound train traveled 10 miles per hour faster than the southbound train.
Draw graph to display problem.
Let the speed of the northbound train, be S
Then the speed of the southbound train = S - 10
Six (6) hours (midnight - 6:00 a.m.) after leaving, the northbound train covered a distance of 6S miles
Three (3) hours (3:00 a.m. - 6:00 a.m.) after leaving, the southbound train covered a distance of 3(S - 10), or 3S - 30 miles
Since they were 330 mile apart at 6:00 a.m., we get the following DISTANCE equation: 6S + 3S - 30 = 330
9S = 360
S, or speed of northbound train = 
Now, subtract 10 from 40 to get the southbound train's speed.
That's it!! Simple enough, right?
Now that the hard part is done, you should be able to graph it. I can't do everything now, can I?
Try it! How else will you learn?
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