SOLUTION: Please help me solve this problem: If xy = 64 and {{{ log (x, y) + log (y, x) = 5/2 }}} find x and y.

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Please help me solve this problem: If xy = 64 and {{{ log (x, y) + log (y, x) = 5/2 }}} find x and y.      Log On


   



Question 1080916: Please help me solve this problem:
If xy = 64 and +log+%28x%2C+y%29+%2B+log+%28y%2C+x%29+=+5%2F2+ find x and y.

Answer by ikleyn(52835) About Me  (Show Source):
You can put this solution on YOUR website!
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Please help me solve this problem:
If xy = 64 and +log+%28x%2C+y%29+%2B+log+%28y%2C+x%29+=+5%2F2+ find x and y.
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log+%28x%2C+y%29+%2B+log+%28y%2C+x%29 = 5%2F2+.      (1)

Well known rule for the base change of logarithms says that  log+%28y%2C+x%29 = 1%2Flog%28x%2Cy%29.

Therefore, the equation (1) becomes

log+%28x%2C+y%29 + 1%2Flog+%28x%2C+y%29 = 5%2F2+.   (2)

To solve it, introduce new variable  z = log+%28x%2C+y%29.  Then the equation (2) becomes

z+%2B+1%2Fz = 5%2F2,   or   z%5E2+-+%285%2F2%29z+%2B+1 = 0,   or   2z%5E2+-+5z+%2B+2 = 0.

Use the quadratic formula to find its roots. The roots are  z%5B1%5D = 2   and/or  z%5B2%5D = 1%2F2.


1.  z%5B1%5D = 2  ====>  log%28x%2Cy%29 = 2  ====>  y = x^2. 

    Substitute it into the equation  xy = 64,  and you will get  x%5E3 = 64,   which implies  x = 4.

    In this case, the solution of the original system is  x = 4,  y = 16.


2.  z%5B2%5D = 1%2F2  ====>  log%28x%2Cy%29 = 1%2F2  ====>  y = x^(1/2). 

    Substitute it into the equation  xy = 64,  and you will get  x^(3/2) = 64,   which implies  x%5E3 = 64%5E2  and hence  x = 16.

    In this case, the solution of the original system is  x = 16,  y = 4.

Answer.  There are two solutions:  1) x=4, y= 16,  and  2) x=16, y = 4.

Solved.


For properties of logarithms and solving logarithmic equations see the lessons
    - WHAT IS the logarithm
    - Properties of the logarithm
    - Change of Base Formula for logarithms
    - Solving logarithmic equations
    - Using logarithms to solve real world problems
in this site.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Logarithms".