SOLUTION: The braking distance D in feet required to stop a car traveling x miles per hour on; dry, level pavement can be approximated by Upper D equals one sixteenth x squared D=
1
16x2.
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-> SOLUTION: The braking distance D in feet required to stop a car traveling x miles per hour on; dry, level pavement can be approximated by Upper D equals one sixteenth x squared D=
1
16x2.
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Question 1080913: The braking distance D in feet required to stop a car traveling x miles per hour on; dry, level pavement can be approximated by Upper D equals one sixteenth x squared D=
1
16x2.
(a) Calculate the braking distance for 30 miles per hour and 70 miles per hour. How do your answers; compare?
(b) If the braking distance is 49 ;feet, estimate the speed of the car.
(c) Use a calculator to solve part (b) numerically. Do your answers agree? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! D=(1/16)x^2, presumably where x is speed in mph
D=(1/16)*900=56.25 feet
D=(1/16)*4900=306.25 feet
Estimate 20-25 mph for stopping distance of 49 feet
49=(1/16)x^2
784=x^2
x=28 mph.
the quadratic form of the equation makes linear estimation difficult.
