SOLUTION: The braking distance D in feet required to stop a car traveling x miles per hour on​ dry, level pavement can be approximated by Upper D equals one sixteenth x squared D=
1
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-> SOLUTION: The braking distance D in feet required to stop a car traveling x miles per hour on​ dry, level pavement can be approximated by Upper D equals one sixteenth x squared D=
1
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Question 1080912: The braking distance D in feet required to stop a car traveling x miles per hour on dry, level pavement can be approximated by Upper D equals one sixteenth x squared D=
1
16x2.
(a) Calculate the braking distance for 3030 miles per hour and 7070 miles per hour. How do your answers compare?
(b) If the braking distance is 4949 feet, estimate the speed of the car.
(c) Use a calculator to solve part (b) numerically. Do your answers agree? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! The braking distance D in feet required to stop a car traveling x miles per hour on dry, level pavement can be approximated by Upper D equals one sixteenth x squared: D = x^2.
(a) Calculate the braking distance for 30 miles per hour and 70 miles per hour. How do your answers compare?
D = *30^2
D =
D = 56.25 ft
&
D = *70^2
D =
D = 326.67ft
:
(b) If the braking distance is 49 feet, estimate the speed of the car.
Estimate 27 mph
(c) Use a calculator to solve part (b) numerically. Do your answers agree? x^2 = 49
x^2 = 49 * 16
x =
x = 28 mph
