SOLUTION: in parallelogram RSTW, diagonals RT and SW intersect at point A. If SA = x+2 and AW = 3x-42, what is the length of SW? I've gone over everything I could to solve it, but I don't ge
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-> SOLUTION: in parallelogram RSTW, diagonals RT and SW intersect at point A. If SA = x+2 and AW = 3x-42, what is the length of SW? I've gone over everything I could to solve it, but I don't ge
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Question 1080893: in parallelogram RSTW, diagonals RT and SW intersect at point A. If SA = x+2 and AW = 3x-42, what is the length of SW? I've gone over everything I could to solve it, but I don't get the answer I need. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! Drawing this, SA=AW, because the diagonals bisect each other in a parallelogram.
Set the two equal and solve for x.
x+2=3x-42
-2x=-44
x=22
x+2=24
3x-42=24, checks.
The length of the diagonal is 24+24 or 48.
