SOLUTION: Mitchell invested part of his $13,000 advance at 5% annual simple interest and the rest at 9% annual simple interest. If his total yearly interest from both accounts was $930&#820

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Question 1080732: Mitchell invested part of his $13,000 advance at 5% annual simple interest and the rest at 9% annual simple interest. If his total yearly interest from both accounts was $930​, find the amount invested at each rate.
What is the amount invested at 5%?
What is the amount invested at 9%?

Found 2 solutions by Fombitz, MathTherapy:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
A - amount invested at 5%
B - amount invested at 9%
1.A%2BB=13000
.
.
.05A%2B.09B=930
2.5A%2B9B=93000
Multiple eq. 1 by 5 and subtract from eq. 2,
5A%2B9B-5A-5B=93000-65000
4A=28000
Solve for A then use either equation to solve for B.

Answer by MathTherapy(10556) About Me  (Show Source):
You can put this solution on YOUR website!
Mitchell invested part of his $13,000 advance at 5% annual simple interest and the rest at 9% annual simple interest. If his total yearly interest from both accounts was $930​, find the amount invested at each rate.
What is the amount invested at 5%?
What is the amount invested at 9%?
Correct answer: