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Question 108063This question is from textbook mathmatics a
: find three consecutive odd integers such that the largest decreased by three times the second is 47 less than the smallest
This question is from textbook mathmatics a
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Just write what it says:
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"find three consecutive odd integers":
x, (x+2, (x+4)
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"the largest decreased by three times the second is 47 less than the smallest":
(x+4) - 3(x+2) = x - 47
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x + 4 - 3x - 6 = x - 47
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-2x - 2 = x - 47
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x - 3x - x = -47 + 2
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-3x = -45
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x = -45/-3
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x = +15, 17, and 19 are the 3 odd integers
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Check solution in the statement:
"largest decreased by three times the second is 47 less than the smallest"
19 - 3(17) = 15 - 47
19 - 51 = -32; confirms our solution
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