SOLUTION: A plane travels at a speed of 155&#8290;mph in still air. Flying with a tailwind, the plane is clocked over a distance of 950 miles. Flying against a headwind, it takes 3 hours lon

Click here to see ALL problems on Travel Word Problems

Question 1080617: A plane travels at a speed of 155⁢mph in still air. Flying with a tailwind, the plane is clocked over a distance of 950 miles. Flying against a headwind, it takes 3 hours longer to complete the return trip. What was the wind velocity?
I think I should have (950/(155-w)) - (950/(155+w)) = 3
but I'm unsure of what to do.
Answer by MathLover1(20850) (Show Source):
You can put this solution on YOUR website!
Initial table of data before analyzing the time quantities; w is tailwind speed.

SPEED TIME DISTANCE WITHWIND 155+w 950 AGAINSTWD 155-w 950

SPEED TIME DISTANCE WITHWIND 155+w 950/(155+w) 950 AGAINSTWD 155-w 950/(155-w) 950

Concentrate on the part of the description, Flying against a headwind, it takes
3 hours longer to complete the return trip.
This means .

The rest is arithmetic to solve the equation for , the speed of the wind.

......using you will get:

SOLUTION: A plane travels at a speed of 155&#8290;mph in still air. Flying with a tailwind, the plane is clocked over a distance of 950 miles. Flying against a headwind, it takes 3 hours lon

SOLUTION: A plane travels at a speed of 155⁢mph in still air. Flying with a tailwind, the plane is clocked over a distance of 950 miles. Flying against a headwind, it takes 3 hours lon