SOLUTION: A farmer can plant 50 coffee plant on a section of land, and the average yield will be 5kg of dried beans per tree. He can plant more plants, but each additional plan reduce the ou
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Question 1080543: A farmer can plant 50 coffee plant on a section of land, and the average yield will be 5kg of dried beans per tree. He can plant more plants, but each additional plan reduce the out put average by 0.09kg. How many plants should he planted on the plot to maximize the total output of the coffee. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A farmer can plant 50 coffee plants on a section of land, and the average yield will be 5kg of dried beans per tree.
He can plant more plants, but each additional plant reduces the output average by 0.09kg.
How many plants should be planted on the plot to maximize the total output of the coffee?
:
let x = the number of trees over 50
let y = amt of dried bean in kg
:
y = (50 + x)(5 - .09x)
FOIL
y = 250 - 4.5 + 5x - .09x^2
the equation
y = -.09x^2 + .5x + 250
The max occurs on the axis of symmetry, find that using x = -b/(2a)
x =
x = 2.78 ~ 3 more trees
We could say that planting 53 trees would give max yield
