|
Question 108053: The problem reads:
Find the equation of the line that is parallel to 6x -3y = 9 and goes through the point (1,6).
I can solve the first part:
y = mx + b
6x = 3y = 9
-3y = -6x + 9
(-1) -3y = (-6x +9)(-1)
3y = 6x - 9
y = 2x - 3
But I need to see how the second part is worked
y - y1 = m(x-x1)
y - 6 = -2(x-1)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find the equation of the line that is parallel to 6x -3y = 9 and goes through the point (1,6).
-----------------
6x-3y=9
3y = 6x-9
y = 2x-3
So. the slope of your parallel line is 2:
-------------
Equation form of the line is y = mx+b
you have y=6,x=1, and m=2; solve for "b".
6 = 2*1+b
b = 4
----------
Equation:
y = 2x+4
==============
Cheers,
Stan H.
|
|
|
| |
