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Let f = the father's rate of work and s = the son's rate of work.
The first equation is
6f + 12s = 1 (1)
The second equation is
9f + 8s = 1. (2).
To solve the system, multiply eq.(1) by 3; multiply eq.(2) by 2 and then subtract. You will have
18f + 36s = 3, (1')
18f + 16s = 2 (2')
------------------------Subtract
====> 20s = 1 ---> s = 1/20.
Thus the son's rate of work is
which means that he will complete the job in 20 hours working alone.
Solved.