SOLUTION:
A BUS LEAVES A STATION AT 1 P.M., TRAVELING WEST AT AN AVERAGE RATE OF 44 MI/H.
ONE HOUR LATER A SECOND BUS LEAVES THE SAME STATION TRAVELING EAST AT A RATE OF 48 MI/H.
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A BUS LEAVES A STATION AT 1 P.M., TRAVELING WEST AT AN AVERAGE RATE OF 44 MI/H.
ONE HOUR LATER A SECOND BUS LEAVES THE SAME STATION TRAVELING EAST AT A RATE OF 48 MI/H.
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Question 108043:
A BUS LEAVES A STATION AT 1 P.M., TRAVELING WEST AT AN AVERAGE RATE OF 44 MI/H.
ONE HOUR LATER A SECOND BUS LEAVES THE SAME STATION TRAVELING EAST AT A RATE OF 48 MI/H.
AT WHAT TIME WILL THE TWO BUSES BE 274 MILES APART?
You can put this solution on YOUR website! 274=44T+48(T-1)
274=44T+48T-48
274=92T-48
92T=274+48
92T=322
T=322/92
T=3.5 HOURS
PROOF
274=44*3.5+48(3.5-1)
274=154+48*2.5
274=154+120
274=274
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