SOLUTION: A large pump can fill a water tank in 8 hours, and a smaller pump can fill it in 24 hours. In order to fill an empty tank, the small pump is operated for 6 hours, and then the larg
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-> SOLUTION: A large pump can fill a water tank in 8 hours, and a smaller pump can fill it in 24 hours. In order to fill an empty tank, the small pump is operated for 6 hours, and then the larg
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Question 1080404: A large pump can fill a water tank in 8 hours, and a smaller pump can fill it in 24 hours. In order to fill an empty tank, the small pump is operated for 6 hours, and then the large pump is also turned on. In total, how many hours will be required to fill the tank this way? Answer by ikleyn(52754) (Show Source):
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The referred lessons are the part of this textbook under the topic "Rate of work and joint work problems" of the section "Word problems".
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Regarding your problem:
The rate of work of the large pump is : it fills of the tank volume per hour.
The rate of work of the small pump is : it fills of the tank volume per hour.
Their combined rate of work is = = = of the tank volume per hour.
After operating for 6 hours, the small pump filled = of the tank volume.
Hence, it will take = = = hours = 4 hours and 30 minutes for two pump to fill
the remaining of the tank volume working together.
