SOLUTION: Solve using the Law of Sines and a scaled drawing. If two triangles exist, solve both completely. Round to the nearest tenth. side a = 16.4 mi B = 54° side b = 25.3 mi

Algebra ->  Finance -> SOLUTION: Solve using the Law of Sines and a scaled drawing. If two triangles exist, solve both completely. Round to the nearest tenth. side a = 16.4 mi B = 54° side b = 25.3 mi       Log On


   

Question 1080292: Solve using the Law of Sines and a scaled drawing. If two triangles exist, solve both completely. Round to the nearest tenth.
side a = 16.4 mi
B = 54°
side b = 25.3 mi
Select one:
a. Not possible
b. A = 31.6°, C = 94.4°, c = 31.2 mi
c. A = 77.5°, C = 38.5°, c = 15.2 mi
d. A = 102.5°, C = 13.5°, c = 5.7 mi
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
side a+=+16.4mi
< B+=+54°
side b+=+25.3mi
a%2F+sin%28+A%29+=+b+%2Fsin+%28B+%29=+c%2F+sin%28+C+%29

a%2F+sin%28+A%29+=+b+%2Fsin+%28B+%29
16.4%2F+sin%28+A%29+=+25.3+%2Fsin+%2854+%29
16.4%2F+sin%28+A%29+=+25.3+%2F0.8090169943749
16.4%2A0.8090169943749++=+25.3+%2Asin%28+A%29
13.26787870774836++=+25.3+%2Asin%28+A%29
13.26787870774836%2F25.3+=sin%28+A%29
0.52442208331+=sin%28+A%29
A+=sin%5E-1%280.52442208331+%29
A+=sin%5E-1%280.52442208331+%29
< A=31.6
then
16.4%2F+sin%28+31.6%29+=+c%2F+sin%28+94.4+%29
16.4%2F+0.52442208331+=+c%2F0.151633

31.2986+=+1.00296+c
31.2986%2F1.00296+=+c
c=31.2
answer is: b.A = 31.6°, C = 94.4°, c = 31.2 mi