SOLUTION: a coin collection consisting of nickels and quarters has a value of $4.50. The number of quarters is 4 less than twice the number of nickels. Find the number of nickel

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Question 1080288: a coin collection consisting of nickels and quarters has a value of $4.50. The number of quarters is 4 less than twice the number of nickels. Find the number of nickel
Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(53763) (Show Source):
You can put this solution on YOUR website!
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a coin collection consisting of nickels and quarters has a value of $4.50. The number of quarters is 4 less
than twice the number of nickels. Find the number of nickel
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Let N be the number of nickels. Then the number of quarters is (2N-4). The "value" equation is 5N + 25*(2N-4) = 450 (cents). 5N + 50N - 100 = 450 ====> 55N = 550 ====> N = 10.

Thanks to "MathTherapy" for pointing my error.

Answer by MathTherapy(10810) (Show Source):
You can put this solution on YOUR website!

a coin collection consisting of nickels and quarters has a value of $4.50. The number of quarters is 4 less than twice the number of nickels. Find the number of nickel

Let number of nickels be N
Then number of quarters = 2N - 4
We then get: .05N + .25(2N - 4) = 4.5
.05N + .5N - 1 = 4.5
.55N = 4.5 + 1
.55N = 5.5
N, or number of nickels =