SOLUTION: Solve for x: 10x^2+12x+4=4

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Question 1080211: Solve for x:
10x^2+12x+4=4
Found 2 solutions by MathLover1, amfagge92:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
10x%5E2%2B12x%2B4=4
10x%5E2%2B12x%2B4-4=0

10x%5E2%2B12x=0
x%2810x%2B12%29=0
solutions for x:
x=0
and
10x%2B12=0=>10x=-12=>x=-12%2F10=>x=-1.2







Answer by amfagge92(93) About Me  (Show Source):
You can put this solution on YOUR website!
10x^2+12x+4=4
10x^2+12x+4-4=0
⇒10x^2+12x=0
2x(5x-6)=0
either 2x=0 or 5x-6=0
⇒X= 0 or X=-6/5.