SOLUTION: A cyclist rode the first 24 mile portion of his workout at a constant speed. For the 16 mile cooldown portion of his​ workout, he reduced his speed by 4 miles per hour. Each

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: A cyclist rode the first 24 mile portion of his workout at a constant speed. For the 16 mile cooldown portion of his​ workout, he reduced his speed by 4 miles per hour. Each       Log On


   

Question 1080137: A cyclist rode the first 24 mile portion of his workout at a constant speed. For the 16 mile cooldown portion of his​ workout, he reduced his speed by 4 miles per hour. Each portion of the workout took the same time. Find the​ cyclist's speed during the first portion and find his speed during the cooldown portion.
Answer by ikleyn(52863) About Me  (Show Source):
You can put this solution on YOUR website!
.
Your equation is

24%2Fr = 16%2F%28r-4%29.


Cross multiply:

24*(r-4) = 16r,

24r - 96 = 16r  --->  24r - 16r = 96  ---->  8r = 96  --->  r = 96%2F8 = 12.


Answer. The speed during the first portion is 12 miles per hour
         and the speed during the rest of the trip was 12-4 = 8 mph.