Question 1079835: In how many ways can 2 red, 2 black, 3 white and 2 blue balls be selected from 4 red, 3 black, 4 white and 8 blue balls? In how many ways can they be arranged?
Answer by addingup(3677)   (Show Source):
You can put this solution on YOUR website! Since you don't say, I assume that 2 red next to each other is a possible arrangement. Or 2 black, or 3 white. In my view, hese are ALL the possible arrangements:
19!/(2!*2!*3!*2!) = 2,534,272,925,184,000
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