SOLUTION: ok, here we go. John and Harry can paint a house in 10 days. when working alone John can paint the house in 30 days. How many days will it take Harry to paint the house. I ha

Algebra ->  Rate-of-work-word-problems -> SOLUTION: ok, here we go. John and Harry can paint a house in 10 days. when working alone John can paint the house in 30 days. How many days will it take Harry to paint the house. I ha      Log On


   



Question 107977: ok, here we go.
John and Harry can paint a house in 10 days. when working alone John can paint the house in 30 days. How many days will it take Harry to paint the house.
I have no idea how to do this probolem.

Found 2 solutions by edjones, ankor@dixie-net.com:
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
The trick is to invert things at first and turn them right side up at the end.
John can do 1/30 of the job in 1 day.
1/30+h=1/10
h=3/30-1/30
h=2/30=1/15 Harry can do 1/15 of the job in one day or the entire job in 15 days.
Ed

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
John and Harry can paint a house in 10 days. when working alone John can paint the house in 30 days. How many days will it take Harry to paint the house.
:
Here's a method you can use on all these kind of problems
:
Let the completed = 1, each will do a fraction that will add up to 1
It's obvious that John will complete 1/3 of the job in 10 days (10/30)
Therefore John has to do 2/3 of the job. What denominator of 10 = 2/3?
:
Let x = Harry's time by himself
:
10%2F30 + 10%2Fx = 1
:
Get rid of the denominators, multiply equation by 30x
:
30x*10%2F30 + 30x*10%2Fx = 30x(1)
:
Cancel out the denominators and you have;
10x + 30(10) = 30x
:
10x - 30x = -300
:
-20x = - 300
:
x = -300/-20
:
x = 15 days required by John by himself
:
:
Check the solution by adding up the fractions
10%2F30 + 10%2F15 =
1%2F3 + 2%2F3 = 1
:
Did this make sense to you? Any questions?