SOLUTION: determine the two number nearest to 9300 which are exactly divisible by each 3,5,7 and 9

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Question 1079763: determine the two number nearest to 9300 which are exactly divisible by each 3,5,7 and 9
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
9%2A5%2A7=315
9300%2F315=29.52
So then rounding up,
315%2A30=9450
and rounding down,
315%2A29=9135