SOLUTION: Not sure if I got the right answer of x=Sqrt27/37 - seems wrong. Thanks in advance. 3log2x = -log2(27)
Algebra
->
Exponential-and-logarithmic-functions
-> SOLUTION: Not sure if I got the right answer of x=Sqrt27/37 - seems wrong. Thanks in advance. 3log2x = -log2(27)
Log On
Algebra: Exponent and logarithm as functions of power
Section
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Exponential-and-logarithmic-functions
Question 1079749
:
Not sure if I got the right answer of x=Sqrt27/37 - seems wrong. Thanks in advance.
3log2x = -log2(27)
Answer by
Alan3354(69443)
(
Show Source
):
You can
put this solution on YOUR website!
show how you got it.
---
You're welcome in advance.