SOLUTION: I know I am no writing this right but I think I have half way, can you help me please: x^2-5x+6 I figured that -2&-3 will be the product of 6 and the sum of -5 but I can figure o

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I know I am no writing this right but I think I have half way, can you help me please: x^2-5x+6 I figured that -2&-3 will be the product of 6 and the sum of -5 but I can figure o      Log On


   



Question 107966: I know I am no writing this right but I think I have half way, can you help me please:
x^2-5x+6
I figured that -2&-3 will be the product of 6 and the sum of -5 but I can figure out how to write it.
Here is my guess: x^2+x(-2*-3)+6. I don't think this is right, can you help me please.Thank you.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


Looking at the expression x%5E2-5x%2B6, we can see that the first coefficient is 1, the second coefficient is -5, and the last term is 6.



Now multiply the first coefficient 1 by the last term 6 to get %281%29%286%29=6.



Now the question is: what two whole numbers multiply to 6 (the previous product) and add to the second coefficient -5?



To find these two numbers, we need to list all of the factors of 6 (the previous product).



Factors of 6:

1,2,3,6

-1,-2,-3,-6



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to 6.

1*6 = 6
2*3 = 6
(-1)*(-6) = 6
(-2)*(-3) = 6


Now let's add up each pair of factors to see if one pair adds to the middle coefficient -5:



First NumberSecond NumberSum
161+6=7
232+3=5
-1-6-1+(-6)=-7
-2-3-2+(-3)=-5




From the table, we can see that the two numbers -2 and -3 add to -5 (the middle coefficient).



So the two numbers -2 and -3 both multiply to 6 and add to -5



Now replace the middle term -5x with -2x-3x. Remember, -2 and -3 add to -5. So this shows us that -2x-3x=-5x.



x%5E2%2Bhighlight%28-2x-3x%29%2B6 Replace the second term -5x with -2x-3x.



%28x%5E2-2x%29%2B%28-3x%2B6%29 Group the terms into two pairs.



x%28x-2%29%2B%28-3x%2B6%29 Factor out the GCF x from the first group.



x%28x-2%29-3%28x-2%29 Factor out 3 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



%28x-3%29%28x-2%29 Combine like terms. Or factor out the common term x-2



===============================================================



Answer:



So x%5E2-5%2Ax%2B6 factors to %28x-3%29%28x-2%29.



In other words, x%5E2-5%2Ax%2B6=%28x-3%29%28x-2%29.



Note: you can check the answer by expanding %28x-3%29%28x-2%29 to get x%5E2-5%2Ax%2B6 or by graphing the original expression and the answer (the two graphs should be identical).