SOLUTION: What is the sum of the two smallest distinct prime factors of 2^{27} + 3^{27}?

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Question 1079492: What is the sum of the two smallest distinct prime factors of 2^{27} + 3^{27}?
Answer by ikleyn(52776) About Me  (Show Source):
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What is the sum of the two smallest distinct prime factors of 2^{27} + 3^{27}?'
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Answer. This sum is 5 + 7 = 12.

Solution

1.  It is clear that 2 is not a factor of  2%5E27+%2B+3%5E27.



2.  It is clear that 3 is not a factor of  2%5E27+%2B+3%5E27.



3.  2%5E27+%2B+3%5E27  has the factor (2 + 3) = 5  since  2%5E27+%2B+3%5E27  has this well known decomposition in the product of these factors:


    2%5E27+%2B+3%5E27 = 


    Thus the first smallest prime factor of the sum  2%5E27+%2B+3%5E27  is 5.



4.  2%5E27+%2B+3%5E27  has the factor 2%5E3+%2B+3%5E3%29 = 35  since  2%5E27+%2B+3%5E27  can be factored in this way:
   

    2%5E27+%2B+3%5E27  = %282%5E3%29%5E9+%2B+%283%5E3%29%5E9 = 8%5E9+%2B+27%5E9 = 


    and (8+27) = 35 is multiple of 7,  so the second smallest prime divisor of this sum is 7 (next after 5).


5.  Therefore, 5 + 7 = 12 is the answer.

Solved.


On factoring binomials x%5En-a%5En and x%5En%2Ba%5En see the lessons
    - Factoring the binomials   x%5En-a%5En
    - Factoring the binomials   x%5En%2Ba%5En for odd degrees
in this site.


Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic
"Factoring binomials x%5En-a%5En and x%5En%2Ba%5En".