SOLUTION: Ben shoots an arrow. The height of the arrow can be modleled at y=-16x^2 +100x + 4, where y represents the height in feet of the arrow x seconds after it is shot into the air. A.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Ben shoots an arrow. The height of the arrow can be modleled at y=-16x^2 +100x + 4, where y represents the height in feet of the arrow x seconds after it is shot into the air. A.      Log On


   



Question 1079402: Ben shoots an arrow. The height of the arrow can be modleled at y=-16x^2 +100x + 4, where y represents the height in feet of the arrow x seconds after it is shot into the air.
A. Graph the height of the arrow
B. At what height was the arrow shot
C. What was the maximum height of the arrow

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+y+=+-16x%5E2+%2B+100x+%2B+4+
(A)
+graph%28+400%2C+400%2C+-2%2C+10%2C+-20%2C+200%2C+-16x%5E2+%2B+100x+%2B+4+%29+
(B)
The arrow was shot at time = 0, which is +x+=+0+
+y+=+-16x%5E2+%2B+100x+%2B+4+
+y%280%29+=+-16%2A0%5E2+%2B+100%2A0+%2B+4+
+y%280%29+=+4+
The arrow was shot from a height of 4 ft
(C)
The x-value of the maximum height is at:
+x%5Bmax%5D+=+-b%2F%282a%29+
+a+=+-16+
+b+=+100+
+x%5Bmax%5D+=+-100%2F%282%2A%28-16%29%29+
+x%5Bmax%5D+=+3.125+ sec
------------------------------
Plug this result back into the equation
to get +y%5Bmax%5D+
+y%5Bmax%5D+=+-16%2A3.125%5E2+%2B+100%2A3.125+%2B+4+
+y%5Bmax%5D+=+-156.25+%2B+312.5+%2B+4+
+y%5Bmax%5D+=+160.25+ ft
---------------------------
Check the math and maybe get another opinion