SOLUTION: Nick has 4 quarters, 3 dimes and 2 nickels in his pocket. He randomly picks 2 coins out of his pocket. What is the probability that he did not choose a dime either time? (Enter yo

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Nick has 4 quarters, 3 dimes and 2 nickels in his pocket. He randomly picks 2 coins out of his pocket. What is the probability that he did not choose a dime either time? (Enter yo      Log On

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Question 1079120: Nick has 4 quarters, 3 dimes and 2 nickels in his pocket. He randomly picks 2 coins out of his pocket. What is the probability that he did not choose a dime either time? (Enter your answer as a whole number percent.) Thank you for your time.

Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
4 quarters, 3 dimes, 2 nickels ---> 9 total coins

probability = (don't pick a dime 1st time) * (don't pick a dime 2nd time)
= (6/9) * (5/8)
= 5/12