SOLUTION: find 3 consecutive even integers such that two times the first integer, plus two times the second integer is equal to six times the third integer

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Question 1079081: find 3 consecutive even integers such that two times the first integer, plus two times the second integer is equal to six times the third integer
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
2n%2B2%28n%2B2%29=6%28n%2B4%29
2n%2B2n%2B4=6n%2B24
4=2n%2B24
2n=-20
n=-10

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Integers: -10, -8, -6
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CHECK:
2%28-10%29%2B2%28-8%29=6%28-6%29
-20-16=-36
-36=-36