SOLUTION: 1.Sketch the graph of y=-x2-2x+3 2.Sketch the graph of y=-x2+2x-2 3.Find the equation for the linear function that is parallel to f(x)=3/2x-3 through (4,-1) 4.Find the equation

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: 1.Sketch the graph of y=-x2-2x+3 2.Sketch the graph of y=-x2+2x-2 3.Find the equation for the linear function that is parallel to f(x)=3/2x-3 through (4,-1) 4.Find the equation       Log On


   

Question 1079056: 1.Sketch the graph of y=-x2-2x+3
2.Sketch the graph of y=-x2+2x-2
3.Find the equation for the linear function that is parallel to f(x)=3/2x-3 through (4,-1)
4.Find the equation of the line that is perpendicular to the equation f(x)=2.5x-0.5 through (-4,2)
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
x^2-2x+3
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E2-2x%2B3%29
-x^2+2x-2
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C-x%5E2%2B2x-2%29
parallel lines have the same slope
point slope formula where y-y1=m(x-x1), m slope, (x1,y1) a point. Watch the signs.
y+1=(3/2)(x-4) and y=(3/2)x-7
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%283%2F2%29x-4%2C%283%2F2%29x-7%29
Perpendicular lines have a negative reciprocal slope
slope of the given line is 5/2, so line perpendicular has a slope of -2/5
y-2=(-2/5)(x+4)
y=(-2/5)x+(2/5)
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C2.5x-0.5%2C%28-2%2F5%29x%2B%282%2F5%29%29