SOLUTION: A boy draws an equilateral triangle PQR .He then drawn three perpendiculars from a point inside of that triangle on three sides of which lengths are 10cm,12cm, and 8cm what is then

Algebra ->  Triangles -> SOLUTION: A boy draws an equilateral triangle PQR .He then drawn three perpendiculars from a point inside of that triangle on three sides of which lengths are 10cm,12cm, and 8cm what is then      Log On


   



Question 1079004: A boy draws an equilateral triangle PQR .He then drawn three perpendiculars from a point inside of that triangle on three sides of which lengths are 10cm,12cm, and 8cm what is then the area of the triangle?
Answer by ikleyn(52879) About Me  (Show Source):
You can put this solution on YOUR website!
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Let "a" be the side length of the given equilateral triangle.

Connect the given point inside the triangle with the vertices by straight segments.


Then the area of the triangle is 

S = %281%2F2%29%2A%2810%2Aa+%2B+12%2Aa+%2B+8%2Aa%29 = %281%2F2%29%2A30a.


From the other side, the area of this triangle is 

S = %28a%5E2%2Asqrt%283%29%29%2F4.


Hence, you have this equation

%281%2F2%29%2A30a = %28a%5E2%2Asqrt%283%29%29%2F4.


From which you have a = %282%2A30%29%2Fsqrt%283%29 = 60%2Fsqrt%283%29 = 20%2Asqrt%283%29.


Then the area of the triangle is 

S = %28a%5E2%2Asqrt%283%29%29%2F4 = %2820%5E2%2A3%2Asqrt%283%29%29%2F4 = %28400%2A3%2Asqrt%283%29%29%2F4 = 300%2Asqrt%283%29 cm%5E2. 


Answer. The area of the triangle is 300%2Asqrt%283%29 cm%5E2.

Solved.