SOLUTION: Find the vertex, focus and directrix of the parabola, {{{ y^2-10y+4x+25=0 }}}

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find the vertex, focus and directrix of the parabola, {{{ y^2-10y+4x+25=0 }}}       Log On


   

Question 1078976: Find the vertex, focus and directrix of the parabola, +y%5E2-10y%2B4x%2B25=0+
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
y%5E2-10y%2B25%2B4x=0

%28y-5%29%5E2%2B4x=0

%28y-5%29%5E2=-4x
-

4p=-4
p=-1


VERTEX (0,5)
FOCUS (-1,5)
DIRECTRIX (1,y) or x=1