SOLUTION: Two polygons are similar with corresponding sides AB=6 in and A'B' =9 in. The large polygon has area 20.25in^2. Find the area of the small polygon.

Algebra ->  Surface-area -> SOLUTION: Two polygons are similar with corresponding sides AB=6 in and A'B' =9 in. The large polygon has area 20.25in^2. Find the area of the small polygon.       Log On


   



Question 1078916: Two polygons are similar with corresponding sides AB=6 in and A'B' =9 in. The large polygon has area 20.25in^2. Find the area of the small polygon.
Answer by MathLover1(20850) About Me  (Show Source):
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By definition, two polygons are similar if and only if their corresponding angles are congruent and there is a proportional relationship among the measures of the corresponding sides.
if corresponding sides AB=6in and A'B' =9in and the large polygon has area A=20.25in%5E2, than the area of the small polygon A' will be:
A:A' =AB:A'B'
20.25in%5E2:A'=6in%3A9in
A'*9in=6in%2A20.25in%5E2
A'*9in=121.5in%5E3
A'=121.5in%5E3%2F9in
A'=13.5in%5E2