SOLUTION: the midpoint of line segment AC is at (2,4); the equation of its perpendicular bisector is y = -(1/2)x + 5, and A is on the x-axis. find the coordinates of C.

Algebra ->  Coordinate-system -> SOLUTION: the midpoint of line segment AC is at (2,4); the equation of its perpendicular bisector is y = -(1/2)x + 5, and A is on the x-axis. find the coordinates of C.       Log On


   

Question 1078913: the midpoint of line segment AC is at (2,4); the equation of its perpendicular bisector is y = -(1/2)x + 5, and A is on the x-axis. find the coordinates of C.
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Line AC contains point (2,4) and has slope 2.
Line AC: y-4=2%28x-2%29
y=2x-4%2B4
y=2x

x and y intercepts for line AC are both (0,0).


Finding endpoint, point C:
Midpoint on AC is (2,4), given.
-
%280%2Bh%29%2F2=2
h%2F2=2
h=4
-
%280%2Bk%29%2F2=4
k%2F2=4
k=8
-
Point C, (4,8).