SOLUTION: Thanks tutor for sloving this: lg(2x)-3lg2={{{(1/2)lg(x-3)}}} lg means log with base 10

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Question 107884: Thanks tutor for sloving this:
lg(2x)-3lg2=%281%2F2%29lg%28x-3%29
lg means log with base 10
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
taking the antilog gives 2x/2^3=sqrt(x-3) ... squaring gives x^2/16=x-3

x^2-16x+48=0 ... (x-12)(x-4)=0