SOLUTION: Use the distance formula to find the equation of a parabola with a focus at (0, 20) and a directrix at the x-axis, y = -10.
y = (1/30)x^2 + 10
y = (1/60)x^2 + 5
y = (1/60)x^2
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-> SOLUTION: Use the distance formula to find the equation of a parabola with a focus at (0, 20) and a directrix at the x-axis, y = -10.
y = (1/30)x^2 + 10
y = (1/60)x^2 + 5
y = (1/60)x^2
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Question 1078733: Use the distance formula to find the equation of a parabola with a focus at (0, 20) and a directrix at the x-axis, y = -10.
y = (1/30)x^2 + 10
y = (1/60)x^2 + 5
y = (1/60)x^2 + 10
y = (1/30)x^2 + 5
You can put this solution on YOUR website! the vertex is at (0,5), half way between the focus and the directrix.
half the distance is 15
This is a y=x^2 type of parabola
(x)^2=4p(y-5)
x^2=60p(y-5)
y=(x^2/60)+5
