SOLUTION: Solve the system of equations by using the substitution method. {x + y = −1 {x^2 + y^2=25 (-4, 3), (4, -3) (-4, -4), (3, 3) (-4, 3), (3, -4) (4, 3), (3, 4)

Algebra ->  Equations -> SOLUTION: Solve the system of equations by using the substitution method. {x + y = −1 {x^2 + y^2=25 (-4, 3), (4, -3) (-4, -4), (3, 3) (-4, 3), (3, -4) (4, 3), (3, 4)       Log On


   

Question 1078731: Solve the system of equations by using the substitution method.
{x + y = −1
{x^2 + y^2=25
(-4, 3), (4, -3)
(-4, -4), (3, 3)
(-4, 3), (3, -4)
(4, 3), (3, 4)
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
x=-y-1
x^2=y^2+2y+1
2y^2+2y+1=25
2y^2+2y-24=0
y^2+y-12=0
(y+4)(y-3)=0
y=-4, 3
y=-4, x=3 and sum of squares=25
y=3, x=-4 and the same thing
(-4, 3)(3, -4)