SOLUTION: Christina and her friends sell chocolate bars during lunch time. They sold 2/5 of the total on day one and sold 1/2 of the leftover on day two. On day three, they sold 1/3 less tha

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Christina and her friends sell chocolate bars during lunch time. They sold 2/5 of the total on day one and sold 1/2 of the leftover on day two. On day three, they sold 1/3 less tha      Log On

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Question 1078438: Christina and her friends sell chocolate bars during lunch time. They sold 2/5 of the total on day one and sold 1/2 of the leftover on day two. On day three, they sold 1/3 less than sales on day one,and are left with 50 left over bars. What was the total chocolate bars they had in the beginning?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +c+ = number of chocolate bars
they had in the beginning
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Day 1
They sold +%282%2F5%29%2Ac+ leaving
+%283%2F5%29%2Ac+
Day 2
They sold +%281%2F2%29%2A%283%2F5%29%2Ac+=+%283%2F10%29%2Ac+
leaving +%283%2F10%29%2Ac+ chocolate bars
Day 3
They sold +%282%2F3%29%2A%282%2F5%29%2Ac+=+%284%2F15%29%2Ac+
so there is +%283%2F10%29%2Ac+-+%284%2F15%29%2Ac+ left
+%289%2F30%29%2Ac+-+%288%2F30%29%2Ac++=+%281%2F30%29%2Ac+
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I am given that:
+%281%2F30%29%2Ac+=+50+
+c+=+1500+
They had 1,500 bars in the beginning
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check the answer:
They sold +%282%2F5%29%2A1500+=+600+ on day1
leaving +1500+-+600+=+900+ bars
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They sold +%281%2F2%29%2A900+=+450+
leaving +450+ bars on day 2
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On day 3 they sold
+%282%2F3%29%2A600+=+400+ bars
+450+-+400+=+50+ bars
OK