SOLUTION: Could someone break this down for me?
1. A random sample of 50 households showed that the average number of tv's in each household is 2.3 with a standard deviation of .4. Find
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1. A random sample of 50 households showed that the average number of tv's in each household is 2.3 with a standard deviation of .4. Find
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Question 1078238: Could someone break this down for me?
1. A random sample of 50 households showed that the average number of tv's in each household is 2.3 with a standard deviation of .4. Find the 90% confidence level for the average number of tv's in every household in the population.
You can put this solution on YOUR website! A random sample of 50 households showed that the average number of tv's in each household is 2.3 with a standard deviation of .4. Find the 90% confidence level for the average number of tv's in every household in the population.
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Sample mean:: 2.3
ME = 1.645*0.4/sqrt(50) = 0.0930
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90% CI:: 2.3-0.0930 < u < 2.3+0.0930
90% CI:: 2.2070 < u < 2.3930
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Cheers,
Stan H.
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