SOLUTION: At $0.31 per​ bushel, the daily supply for wheat is 450 ​bushels, and the daily demand is 567567 bushels. When the price is raised to $0.76 per​ bushel, the daily

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: At $0.31 per​ bushel, the daily supply for wheat is 450 ​bushels, and the daily demand is 567567 bushels. When the price is raised to $0.76 per​ bushel, the daily      Log On


   



Question 1078185: At $0.31 per​ bushel, the daily supply for wheat is 450 ​bushels, and the daily demand is 567567 bushels. When the price is raised to $0.76 per​ bushel, the daily supply increases to 600600 ​bushels, and the daily demand decreases to 492
bushels. Assume that the​ price-supply and​ price-demand equations are linear.

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
(0.31,450) and (0.76,600) is supply equation, with slope 150/0.45=333.3
equation uses point slope y-y1=m(x-x1) m slope (x1,y1) the point
y-600=333.3(x-0.76)
y=333.3x+346.6667
=============================
(0.31,567) and (0.76, 492) with slope -75/0.45=-1.66667
y-492=-1.6667*(x-0.76)
y=-1.6667x+493.2667
============================
graph%28300%2C300%2C-1%2C10%2C450%2C540%2C333.3x%2B346.6667%2C-1.6667x%2B493.2667%29
set the two equal
-1.6667x+493.2667=333.3x+346.6667
335x=146.666
x=0.438 or 0.44 cents/bushel
493 bushels with the first equation.
492.54 bushels with the second equation, rounding error.