SOLUTION: You toss a nickel, a dime, and a quarter once each. Let E be the event that at most one of the coins comes up tails, and let F be the event that the quarter comes up heads. (N

Algebra ->  Probability-and-statistics -> SOLUTION: You toss a nickel, a dime, and a quarter once each. Let E be the event that at most one of the coins comes up tails, and let F be the event that the quarter comes up heads. (N      Log On


   



Question 1078168: You toss a nickel, a dime, and a quarter once each.
Let E be the event that at most one of the coins comes up tails,
and let F be the event that the quarter comes up heads.
(Note: "P(E)= probability of the event E")
Find the following:

1. n (E ∩ F)
2. P(E)
3. P(F)

4. P(E ∩ F)

Answer by Edwin McCravy(20064) About Me  (Show Source):
You can put this solution on YOUR website!
Sample space = S = {HHH,HHT,HTH,HTT,THH,THT,TTH,TTT},

The sample space S has 8 elements, i.e., n(S) = 8

where the first letter represents how the nickel came up,
the second letter represents how the dime came up, and
the third letter represents how the quarter came up.

E = {HHH,HHT,HTH,THH}. There are 4 elements so n(E) = 4

F = {HHH,HTH,THH,TTH}. There are 4 elements so n(F) = 4

1. n(E ∩ F) = n({HHH,HHT,HTH,THH} ∩ {HHH,HTH,THH,TTH}) = n({HHH,HTH,THH})
[Note: ∩ means to take ONLY the elements in common.]

There are 3 elements so n(E ∩ F) = 3

2. P(E) = n(E)/n(S) = 4/8 = 1/2 

3. P(F) = n(F)/n(S) = 4/8 = 1/2 

4. P(E ∩ F) = n(E ∩ F)/n(S) = 3/8

Edwin