Notice that the preceding answer 1.5 hrs, could not be correct because
Jim alone could paint the door in 1 hour. Surely Kim couldn't slow
Jim down that much. LOL
Kim can paint the garage door in 2 hours and Jim can paint the same door in 1 hour. How long will it take them if they work together?
You can do it with or without algebra.
Without algebra, just basic math:
If both work together for 2 hours painting garage doors
(say in a new development of houses), Kim will paint
1 garage door while Jim, the faster will paint 2 garage
doors, so together they can paint 3 garage doors in 2
hours. So they can paint 1 garage door in 1/3 of 2 hours
which is 1/3 of 120 minutes or 40 minutes.
With algebra:
How long will it take them if they work together?
Let the answer be x hours.
Kim can paint the garage door in 2 hours.
So Kim's painting rate is 1 door per 2 hours or
or
Jim can paint the same door in 1 hour
So Kim's painting rate is 1 door per 1 hour or
or
Together they can paint the same door in x hours:
So together their combined painting rate is 1 door per x hours or
or
The equation comes from:


Multiply through by 2x






2/3 of an hour is 2/3 of 60 minutes = 40 minutes.
Edwin