SOLUTION: the probabilities that a service station will pump gas into 0, 1, 2, 3, 4, or 5 or more cars during a certain 30-minute period are 0.03, 0.18, 0.24, 0.28, 0.10, 0.17 respectively.
Algebra ->
Probability-and-statistics
-> SOLUTION: the probabilities that a service station will pump gas into 0, 1, 2, 3, 4, or 5 or more cars during a certain 30-minute period are 0.03, 0.18, 0.24, 0.28, 0.10, 0.17 respectively.
Log On
Question 1078021: the probabilities that a service station will pump gas into 0, 1, 2, 3, 4, or 5 or more cars during a certain 30-minute period are 0.03, 0.18, 0.24, 0.28, 0.10, 0.17 respectively. find the probability that in this 30-minute period
a) more than 2 cars receive gas
b) at most 4 cars receive gas
c) P(4 or more cars) Answer by Edwin McCravy(20064) (Show Source):
If n = the number of cars that pump gas, then
P(n=0) = 0.03
P(n=1) = 0.18
P(n=2) = 0.24
P(n=3) = 0.28
P(n=4) = 0.10
P(n≥5) = 0.17
Easy. Just add the probabilities of how many
cars might pump. I'll do the first one. You
do the other two:
a) more than 2 cars receive gas
There could be 3, 4, or more than 5
P(n=3 or n=4 or n≥5) = P(n=3)+P(n=4)+P(n≥5) =
0.28 + 0.10 + 0.17 = 0.55
----------
Edwin
