SOLUTION: An object moving vertically is at the given heights at the specified times. Find the position equation. s = beveled 1 halfat2 + v0t + s0 for the object given the following condi

Algebra ->  Test -> SOLUTION: An object moving vertically is at the given heights at the specified times. Find the position equation. s = beveled 1 halfat2 + v0t + s0 for the object given the following condi      Log On


   



Question 1077731: An object moving vertically is at the given heights at the specified times. Find the position equation.
s = beveled 1 halfat2 + v0t + s0 for the object given the following conditions.
the 0's are subscripts
At t = 1 seconds, s = 48 feet
At t = 2 seconds, s = 64 feet
At t = 3 seconds, s = 48 feet
A.) +s+=+16t%5E2+-+96t+%2B+192+
B.) +s+=+32t%5E2+-+96t+%2B+192+
C.) +s+=+-16t%5E2+%2B+64t+%2B+0+
D.) +s+=+-32t%5E2+%2B+64t+

Found 2 solutions by ikleyn, josmiceli:
Answer by ikleyn(52794) About Me  (Show Source):
You can put this solution on YOUR website!
.
Do you want I calculate it instead of you ?



Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The general form is:
+s%28t%29+=+a%2At%5E2+%2B+b%2At+%2B+c+
---------------------------
(1)
+s%281%29=+48+
+48+=+a%2A1%5E2+%2B+b%2A1+%2B+c+
+a+%2B+b+%2B+c+=+48+
----------------------------
(2)
+s%282%29+=+64+
+64+=+a%2A2%5E2+%2B+b%2A2+%2B+c+
+4a+%2B+2b+%2B+c+=+64+
-----------------------------
(3)
+s%283%29+=+48+
+48+=+a%2A3%5E2+%2B+b%2A3+%2B+c+
+9a+%2B+3b+%2B+c+=+48+
-----------------------------
From (1) and (3)
+a+%2B+b+%2B+c+=+9a+%2B+3b+%2B+c+
+a+%2B+b+=+9a+%2B+3b+
+8a+=+-2b+
(1) +b+=+-4a+
------------------
Subtract (1) from (2)
+4a+%2B+2b+%2B+c+=+64+
+-a+-+b+-+c+=+-48+
----------------------
(2) +3a+%2B+b+=+16+
Plug (1) into (2)
+3a+-+4a+=+16+
+a+=+-16+
---------------------
and
(1) +b+=+-4a+
(1) +b+=+-4%2A%28-16%29+
(1) +b+=+64+
---------------------
+9a+%2B+3b+%2B+c+=+48+
+9%2A%28-16%29+%2B+3%2A64+%2B+c+=+48+
+-144+%2B+192+%2B+c+=+48+
+c+=+144+-+192+%2B+48+
+c+=+0+
---------------------
So, I have:
+a+=+-16+
+b+=+64+
+c+=+0+
The answer is (C) +-16t%5E2+%2B+64t+%2B+0+