SOLUTION: Suppose an object is thrown upward with an initial velocity of 52 feet per second from a height of 125 feet. The height of the object t seconds after it is thrown is given by h(t)=
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Question 1077319: Suppose an object is thrown upward with an initial velocity of 52 feet per second from a height of 125 feet. The height of the object t seconds after it is thrown is given by h(t)=-16t^2+52t+125.Find the average velocity in the first three seconds after the object is thrown. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Suppose an object is thrown upward with an initial velocity of 52 feet per second from a height of 125 feet. The height of the object t seconds after it is thrown is given by h(t)=-16t^2+52t+125. Find the average velocity in the first three seconds after the object is thrown.
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Avg speed = change in height divided by 3.
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h(t)=-16t^2+52t+125
Change in height = h(3) - h(0)
