SOLUTION: A model rocket is launched with an initial velocity of 164 ​ft/sec. Its height​ h, in​ feet, after t seconds is given by the formula h =16t^2-164t. After how many
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-> SOLUTION: A model rocket is launched with an initial velocity of 164 ​ft/sec. Its height​ h, in​ feet, after t seconds is given by the formula h =16t^2-164t. After how many
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Question 1077131: A model rocket is launched with an initial velocity of 164 ft/sec. Its height h, in feet, after t seconds is given by the formula h =16t^2-164t. After how many seconds will the rocket first reach a height of 348 ft?
You can put this solution on YOUR website! I think the proper equation for a projectile is h=-16tē+vt, where v is the initial velocity. Using that, we get:
348=-16tē+164t
So:
16tē-164t+348=0
4tē-41t+87=0
(4t-29)(t-3)=0
t=29/4 or 3
Using t=3 as our value, we get 3 seconds after launch as the time the rocket first reaches 348 ft. ☺☺☺☺
