SOLUTION: CAR A TRAVELING AT 35 MILES PER HOUR. CAR B IS 200 FEET BEHIND CAR A. AT WHAT SPEED MUST CAR B TRAVEL TO CATCH UP TO CAR A?

Algebra ->  Matrices-and-determiminant -> SOLUTION: CAR A TRAVELING AT 35 MILES PER HOUR. CAR B IS 200 FEET BEHIND CAR A. AT WHAT SPEED MUST CAR B TRAVEL TO CATCH UP TO CAR A?       Log On


   



Question 1077070: CAR A TRAVELING AT 35 MILES PER HOUR. CAR B IS 200 FEET BEHIND CAR A. AT WHAT SPEED MUST CAR B TRAVEL TO CATCH UP TO CAR A?

Found 2 solutions by josmiceli, ikleyn:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
If car B travels at +35+ mi/hr, it will never catch up
to car A -it will always be +200+ ft behind, so any
speed greater than +35+ mi/hr will allow it to catch up
----------------------
Suppose B's speed = +45+ mi/hr
Let +d+ = distance that B travels until it catches A
Let +t+ = time in hrs for B to catch A
Convert +200+ ft to miles: +200%2F5280+
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Equation for A:
(1) +d+-+200%2F5280+=+35t+
Equation for B:
(2) +d+=+45t+
-------------------------
Plug (2) into (1)
(1) +d+-+200%2F5280+=+35t+
(1) +45t+-+200%2F5280+=+35t+
(1) +10t+=+200%2F5280+
(1) +t+=+20%2F5280+
(1) +t+=+.003788+ hrs
Convert hrs to sec
+.003788%2A3600+=+13.64+
B will catch A in 13.64 sec
--------------------------
Plug back into (2) to find +d+
Hope this helps

Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.
Formally, the necessary and the sufficient condition is this: "the car B must move at the speed higher than the car A".

And if the condition is in place and if the two cars move for a sufficiently long time, then the car B INEVITABLY will catch up the car A.


If you want to learn MORE about solving "catching-up" problems, read the lesson
    - Travel and Distance problems for two bodies moving in the same direction (catching up)
in this site.