SOLUTION: One number is 3 less than another. If 10 times the smaller number minus 3 times the larger number is 33, find the two numbers.

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Question 107704: One number is 3 less than another. If 10 times the smaller number minus 3 times the larger number is 33, find the two numbers.
Answer by solver91311(24713) About Me  (Show Source):
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Let the first number be x. Then the other number must be x + 3.
10 times the first number is 10x, and 3 times the other number is 3(x + 3) so subtracting gives you:

10x-3%28x%2B3%29=+33
10x-3x-9=33
7x-9=33
7x=42
x=6
The smaller number is 6, and the larger is 9.

Check:

10%2A6-3%2A9=33
60-27=33 Check