SOLUTION: In an a.p the sum of the squares of the five consecutive series is 20time the square of the middle term,and the product of the five terms equals to 80.What is the middle term.

Algebra ->  Sequences-and-series -> SOLUTION: In an a.p the sum of the squares of the five consecutive series is 20time the square of the middle term,and the product of the five terms equals to 80.What is the middle term.       Log On


   



Question 1076783: In an a.p the sum of the squares of the five consecutive series is 20time the square of the middle term,and the product of the five terms equals to 80.What is the middle term.

Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let "a" be the middle term of the AP, and "d" be the common difference.
Then you have these equations

%28a-2d%29%5E2+%2B+%28a-d%29%5E2+%2B+a%5E2+%2B+%28a%2Bd%29%5E2+%2B+%28a%2B2d%29%5E2 = 20%2Aa%5E2,    (1)    and

%28a-2d%29%2A%28a-d%29%2Aa%2A%28a%2Bd%29%2A%28a%2B2d%29 = 80.             (2)


Simplify (1) and (2):

5a%5E2+%2B+10d%5E2 = 20%2Aa%5E2          (1')     and
a%2A%28a%5E2-d%5E2%29%2A%28a%5E2-4d%5E2%29 = 80    (2')


Simplify (1'):

a%5E2+%2B+2d%5E2 = 4a%5E2,   which is the same as  3a%5E2 = 2d%5E2,  which is the same as

d%5E2 = %283%2F2%29%2Aa%5E2.               (1'')


Then (2') becomes (after substitution (1'') )

a%2A%28a%5E2+-+%283%2F2%29%2Aa%5E2%29%2A%28a%5E2+-+4%2A%283%2F2%29%2Aa%5E2%29 = 80,   or

a%2A%28%28-1%2F2%29%2Aa%5E2%29%2A%28-5a%5E2%29 = 80,   or

a%5E5 = %2880%2A2%29%2F5 = 32.


Then a = root%285%2C32%29 = 2.


Answer.  The middle term under the question is 2.

Solved.