SOLUTION: Find the solutions to the equation: x2 + 2x – 8 = 0. a. x = –4, 2 b. x = –3, 5 c. x = –2, 4 d. x = 4, 4

Algebra ->  Rational-functions -> SOLUTION: Find the solutions to the equation: x2 + 2x – 8 = 0. a. x = –4, 2 b. x = –3, 5 c. x = –2, 4 d. x = 4, 4      Log On


   



Question 107670: Find the solutions to the equation: x2 + 2x – 8 = 0.
a. x = –4, 2
b. x = –3, 5
c. x = –2, 4
d. x = 4, 4

Found 2 solutions by jim_thompson5910, MathLover1:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:


Starting with the general quadratic


ax%5E2%2Bbx%2Bc=0


the general solution using the quadratic equation is:


x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29




So lets solve x%5E2%2B2%2Ax-8=0 ( notice a=1, b=2, and c=-8)





x+=+%28-2+%2B-+sqrt%28+%282%29%5E2-4%2A1%2A-8+%29%29%2F%282%2A1%29 Plug in a=1, b=2, and c=-8




x+=+%28-2+%2B-+sqrt%28+4-4%2A1%2A-8+%29%29%2F%282%2A1%29 Square 2 to get 4




x+=+%28-2+%2B-+sqrt%28+4%2B32+%29%29%2F%282%2A1%29 Multiply -4%2A-8%2A1 to get 32




x+=+%28-2+%2B-+sqrt%28+36+%29%29%2F%282%2A1%29 Combine like terms in the radicand (everything under the square root)




x+=+%28-2+%2B-+6%29%2F%282%2A1%29 Simplify the square root (note: If you need help with simplifying the square root, check out this solver)




x+=+%28-2+%2B-+6%29%2F2 Multiply 2 and 1 to get 2


So now the expression breaks down into two parts


x+=+%28-2+%2B+6%29%2F2 or x+=+%28-2+-+6%29%2F2


Lets look at the first part:


x=%28-2+%2B+6%29%2F2


x=4%2F2 Add the terms in the numerator

x=2 Divide


So one answer is

x=2




Now lets look at the second part:


x=%28-2+-+6%29%2F2


x=-8%2F2 Subtract the terms in the numerator

x=-4 Divide


So another answer is

x=-4


So our solutions are:

x=2 or x=-4





So the answer is A)

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
Find the solutions to the equation:
x%5E2%2B2x-8=0
a. x= (-4, 2)
b. x= (-3, 5)
c. x= (-2, 4)
d. x = (4, 4)
use quadratic formula:

In the standard form
ax%5E2+%2Bbx+%2Bc+=+0++
the roots are:
x%5B1%2C2%5D=%28-b+%2B-+sqrt+%28b%5E2+-4%2Aa%2Ac+%29%29+%2F+%282%2Aa%29
since you have: a=1, b=2, and c=-8
then:
x%5B1%2C2%5D=%28-2+%2B-+sqrt+%282%5E2+-4%2A1%2A%28-8%29+%29%29+%2F+%282%2A1%29
x%5B1%2C2%5D=%28-2+%2B-+sqrt+%284+%2B+32+%29%29+%2F+2
x%5B1%2C2%5D=%28-2+%2B-+sqrt+%2836+%29%29+%2F+2
x%5B1%2C2%5D=%28-2+%2B-+%286+%29%29+%2F+2
x%5B1%5D=%28-2+%2B+6%29+%2F+2
x%5B1%5D=+4+%2F+2
x%5B1%5D=+2
x%5B2%5D=%28-2+-+6+%29+%2F+2

x%5B2%5D=+-+8%2F+2
x%5B2%5D=+-+4

answer is a.