SOLUTION: BJ has a bag of marbles. 9 are black, 8 are red, 7 are white, and 5 are green. Without looking BJ draws two marbles. He replaces the first marble before drawing the second marble.

Algebra ->  Statistics  -> Normal-probability -> SOLUTION: BJ has a bag of marbles. 9 are black, 8 are red, 7 are white, and 5 are green. Without looking BJ draws two marbles. He replaces the first marble before drawing the second marble.      Log On


   

Question 1076589: BJ has a bag of marbles. 9 are black, 8 are red, 7 are white, and 5 are green.
Without looking BJ draws two marbles. He replaces the first marble before drawing the second marble. Compute the probability that he first picks a black marble and then a green one.
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
with replacement, the probability of black and then green is (9/29)*(5/29)=45/841 or 0.053